Question on: WAEC Mathematics - 2006
(\begin{array}{c|c} x & 1 & 4 & p \ \hline y & 0.5 & 1 & 2.5\end{array}). The table below satisfies the relation y - k(\sqrt{x}), where k is a positive constant. Find the value of P,
A
2
B
4
C
10
D
25
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Correct Option: D
From y = (\frac{1}{2} \sqrt{x})
when y = 2.5 or (\frac{5}{2}), x = P
(\frac{5}{2} \times \frac{1}{2} \sqrt{P})
(\sqrt{P} = \frac{10}{2} = 5)
P = 52
= 25
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